3-5(2x-1)^2/5=-17

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Solution for 3-5(2x-1)^2/5=-17 equation: 


x in (-oo:+oo)

3-((5*(2*x-1)^2)/5) = -17 // + 17

3-((5*(2*x-1)^2)/5)+17 = 0

3-(2*x-1)^2+17 = 0

3-1*(2*x-1)^2+17 = 0

3-1*(2*x-1)^2+17 = 0

4*x-4*x^2+2+17 = 0

4*x-4*x^2+19 = 0

4*x-4*x^2+19 = 0

4*x-4*x^2+19 = 0

DELTA = 4^2-(-4*4*19)

DELTA = 320

DELTA > 0

x = (320^(1/2)-4)/(-4*2) or x = (-320^(1/2)-4)/(-4*2)

x = (8*5^(1/2)-4)/(-8) or x = (-8*5^(1/2)-4)/(-8)

(x-((8*5^(1/2)-4)/(-8)))*(x-((-8*5^(1/2)-4)/(-8))) = 0

(x-((8*5^(1/2)-4)/(-8)))*(x-((-8*5^(1/2)-4)/(-8))) = 0

( x-((-8*5^(1/2)-4)/(-8)) )

x-((-8*5^(1/2)-4)/(-8)) = 0 // + (-8*5^(1/2)-4)/(-8)

x = (-8*5^(1/2)-4)/(-8)

( x-((8*5^(1/2)-4)/(-8)) )

x-((8*5^(1/2)-4)/(-8)) = 0 // + (8*5^(1/2)-4)/(-8)

x = (8*5^(1/2)-4)/(-8)

x in { (-8*5^(1/2)-4)/(-8), (8*5^(1/2)-4)/(-8) }

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